Method of Undetermined Coefficients: Example
Find a particular solution to the
equation
Solution: Let us follow these steps:
-
- (1)
- First, we notice that the conditions are satisfied to invoke
the method of undetermined coefficients.
- (2)
- We split the equation into the following three equations:
- (3)
- The root of the characteristic equation are
r=-1 and r=4.
- (4.1)
- Particular solution to Equation (1):
-
- Since , and , then ,
which is not one of the roots. Then s=0.
-
- The particular solution is given as
-
- If we plug it into the equation (1), we get
,
which implies A = -1/2, that is,
- (4.2)
- Particular solution to Equation (2):
-
- Since , and , then ,
which is not one of the roots. Then s=0.
-
- The particular solution is given as
-
- If we plug it into the equation (2), we get
,
which implies
Easy calculations give
,
and
,
that is
- (4.3)
- Particular solution to Equation (3):
-
- Since , and , then
which is one of the roots. Then s=1.
-
- The particular solution is given as
-
- If we plug it into the equation (3), we get
,
which implies
,
that is
- (5)
- A particular solution to the original equation is
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Amine Khamsi
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