Hi guys,
can you check my work.
i would like to solve for the pair Combinations/Probability given that 8 decks are currently used.
here's my solution.
combination(13,1)*combination(32,2)*combination(416,2)
so there's 13 types of cards in a deck (A,2,3,.....,Q,K)
then each card is consist of 32 cards in 8 deck
then total number of cards is 416.
is my solution right or should i use the law of total probability. in order to get the
probability of having a pair.THANK YOU SO MUCH
The probability of getting a pair in two consecutive draws without replacement is: