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PostPosted: Sun, 25 Oct 2020 05:28:54 UTC 
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Show that there are no a,b,c,d\in \mathbb{Q}(i) such that e^{2\pi i/5}=a+b\sqrt[4]{2}+c\sqrt{2}+d(\sqrt[4]{2})^{-1}

Previously in this problem, I found all the subfields of \mathbb{Q}(\sqrt[4]{2},i) with the help of the subgroups of D_4 and Galois's Theorem as you can see in the following image:

Image

Additionally, I have the following idea:
e^{2\pi i /5}=a+b\sqrt[4]{2}+c(\sqrt[4]{2})^2+\frac{d}{2}(\sqrt[4]{2})^3 with a,b,c,d\in\mathbb{Q}(i).Therefore e^{2\pi i /5}\in \mathbb{Q}(\sqrt[4]{2},i).

If I could prove that e^{2\pi i /5}\not\in \mathbb{Q}(\sqrt[4]{2},i) I would have the request but I don't know how to use the subfields found in the image for this (or maybe it should be solved another way)

How can proves this?


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