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PostPosted: Fri, 13 Mar 2020 22:22:19 UTC 
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- notation: x+y:=\mbox{OR}(x,y), \bar x:=\mbox{NOT}(x), xy:=\mbox{AND}(x,y), 1:=TRUE, 0:=FALSE.

- Let f be a Boolean function of n-variables, i.e. f: \{0,1\}^n \to \{0,1\}.
- minterm:= any product (AND) of n literals (complemented or uncomplemented). e.g, x_1 \bar x_2 x_3 is a minterm in 3 variables

- \mbox{NOR2}(f) is the minimum number of 2-input NOR gates required to represent a given function f. For instance, \mbox{NOR2}(x_1 x_2)=3.

Let f_1= m_1, f_2=m_2, where m_1, m_2 are minterms that are **co-prime** (i.e, f_1+f_2 can't be minimized further. In other words, m_1,m_2 are prime implicants of f_1+f_2). For instance, x_1 \bar x_2 x_3 and x_1 x_2 \bar x_3 are co-prime

Then, is the following true?
\mbox{NOR2}(f_1+f_2)\ge \mbox{max}\{ \mbox{NOR2}(f_1), \mbox{NOR2}(f_2) \}

[i.e, adding two coprime minterms can't yield a 2-input NOR circuit with fewer gates]

I think it is true but I can't think of a proof. Any ideas on how to start proving it?


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